(x+6)(x^3-3x+2)=0

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Solution for (x+6)(x^3-3x+2)=0 equation: 


Simplifying
(x + 6)(x3 + -3x + 2) = 0

Reorder the terms:
(6 + x)(x3 + -3x + 2) = 0

Reorder the terms:
(6 + x)(2 + -3x + x3) = 0

Multiply (6 + x) * (2 + -3x + x3)
(6(2 + -3x + x3) + x(2 + -3x + x3)) = 0
((2 * 6 + -3x * 6 + x3 * 6) + x(2 + -3x + x3)) = 0
((12 + -18x + 6x3) + x(2 + -3x + x3)) = 0
(12 + -18x + 6x3 + (2 * x + -3x * x + x3 * x)) = 0
(12 + -18x + 6x3 + (2x + -3x2 + x4)) = 0

Reorder the terms:
(12 + -18x + 2x + -3x2 + 6x3 + x4) = 0

Combine like terms: -18x + 2x = -16x
(12 + -16x + -3x2 + 6x3 + x4) = 0

Solving
12 + -16x + -3x2 + 6x3 + x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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